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What is the mass of heavy water, D2O(l), produced when 5.55g of O2(g) reacts with excess D2(g)?
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consider the reaction 2D2(g)+O2(g)→2D2O(l)
If you've got 5.55g of Oxygen on the left side of the equation, how much will you have on the right, after it has formed into deuterium oxide?
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