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OpenStudy (anonymous):
(x-1)(x+3)=12
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OpenStudy (anonymous):
\[x ^{2}+3x-x-3=12\] \[x ^{2}+2x-15=0\] \[(x-3)(x+5)=0\] Therefore \[ 0=x-3\] \[ x=3\] and \[ 0=x+5\] \[ x=-5\]
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