Question

Let x and y be real numbers with x>y such that x^2 y^2 + x^2 + y^2 + 2xy = 40 and xy + x + y = 8. Find the value of x.

Answer 1

take second eqn as x+y=8-xy
then squaring on both sides
and then simplify it using first eqn
u vl get 2 solutions then using condition x>y find x.....