Question

15=8x^2-14x

Answer 1

rearrange \[ax^2+bx+c=0\]
then apply the quadratic formula
\[x_{1,2}=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\]

Answer 2

its easier to re write it backwards.

Answer 3

14x-2^8x=15
6x-2^=15
6x=16.4
x=2.73

Answer 4

1. Subtract 15 from both sides to set the equation equal to 0:

_ 8x^2 - 14x - 15 = 0

2. Factor your equation into two binomials:

_ (4x + 3) * (2x - 5)

3. Set each binomial equal to 0.

_ 4x + 3 = 0
_ 2x - 5 = 0

4. In the first binomial, subtract 3 from both sides. In the second binomial, add 5 to both sides.

_ 4x = -3
_ 2x + 5

5. Now we need to find "x" by itself. Divide each equation by x's coefficient (the number in front of the x)

_ x = (-3/4)
_ x = (5/2)

6. Those are your two answers! Hope this helps.