Pls help ....
represent √3cos(a) + sine(a) in the form of Rcos[a-b] where R,b are real numbers.
hence solve this expression for (a)

√3cos^2(a) + (1+√3)sin(a)cos(a) - sin^2(a) - cos(a) + sin(a) = 0

I know that the answer for 1st part is 2cos[a - pi/6]
but I cant use it to get the answer for second one...

Question

Pls help ....
  represent √3cos(a) + sine(a) in the form of                                  Rcos[a-b] where R,b are real numbers.
   hence solve this expression for (a)

√3cos^2(a) + (1+√3)sin(a)cos(a) - sin^2(a) - cos(a) + sin(a) = 0

I know that the answer for 1st part is 2cos[a - pi/6]
but I cant use it to get the answer for second one...

***[isuru]*** · Answer

@UnkleRhaukus  , @ganeshie8  @thisSucks  @thomaster  @ybarrap  @oksuz_  @AravindG  @abb0t   pls help