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OpenStudy (anonymous):
To find the sum of consecutive integers, starting at 1, we use the formula n(n+1)/2 where n is the last number. Find the sum of the numbers from 1 to 100. 1 + 2 + 3 + ... + 100 A.101 B.1,001 C.5,000 D.5,050
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OpenStudy (anonymous):
n is the last number so it has to be 100. Let's try 100x100+1/2 see what everybody gets
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