Question

To find the sum of consecutive integers, starting at 1, we use the formula n(n+1)/2 where n is the last number. Find the sum of the numbers from 1 to 100.

1 + 2 + 3 + ... + 100
A.101
B.1,001
C.5,000
D.5,050

Answer 1

n is the last number so it has to be 100. Let's try 100x100+1/2 see what everybody gets