Question

Help Operations of Complex Numbers 5 questions short

Answer 1

@happinessbreaksbones can you please help me and explain

Answer 2

(1+3i)+(2-5i) = 1 + 2 + 3i - 5i = 3 - 2i

Answer 3

I wish I could help but math is not my best subject D:

someone will help you though. my apologies.

Answer 4

(6+2i)-(8-3i) = 6 - 8 + 2i - - 3i = -2 +5i

Answer 5

@Herbvan You help me Thanks :)

Answer 6

( 1 + 2i ) * ( 5 - 3i ) = ( 1 * 5) + (1 * -3i) + ( 2i * 5) + ( 2i * -3i ) = 5 -3i +10i -6*-1 = 11 + 7i

Answer 7

(-3 + 2i) * ( 2 + i ) = ( -3 * 2 ) + ( -3 * i ) + (2i * 2) + (2i * i) = -6 -3i + 4i + 2*-1 = 8 + i

Answer 8

is it negative 8+1?

Answer 9

true :") woops

Answer 10

-8+i

Answer 11

yea :)

Answer 12

and the last one, rationalize the denominator by miltiplying the enitre thing by ( (3+2i)/(3+2i)

Answer 13

u have enough examples now :)

Answer 14

is it c?@HerbvanH

Answer 15

yup :)

Answer 16

thanks for the help if i need help can I @ you

Answer 17

If i'm there i'll help :)

Answer 18

@HerbvanH I have this I have the answer just want to know if its right

Answer 19

the second term looks like a 3rd order power of x, not a 6th

Answer 20

but i am not familiar with these kinds of questions posed this way, and english is not my native tongue

Answer 21

ohh okay