Question

Find dy/dx, using implicit differentiation the equation is 2x + 9y= xy

Answer 1

\[2x+9y=xy\]\[2+9y'=y+xy'\]\[9y'-xy'=y-2\]\[y'(9-x)=y-2\]\[y'=(y-2)/(9-x)\]

Answer 2

what happens to the x at the veyr beginning?

Answer 3

very*

Answer 4

f(x)=y that's why when y(which is originally f(x) or x) is multiplied to y1 the y(which is originally f(x) or x) got cancelled.