Question

In the diagram of △ABC shown below, BC = 10 and AB = 16. To the nearest tenth of a degree, what is the measure of the largest acute angle in the triangle? Right Triangle ABC with right angle C

Answer 1

Diagram is attached.

Side AC² = 16² - 10²
Side AC² = 256 -100
Side AC = sq root(156)
Side AC = 12.49

Sine A = 10 / 16
Sine A = .625
Angle A = arc sin (.625)
Angle A = 38.682 Degrees There fore
Angle B = 180-90-38.682 = 51.318°
Angle B is the largest of the 2 acute angles and it equals 51.318°