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Mathematics 17 Online
OpenStudy (anonymous):

How to prove 0.999999....=1 ?

OpenStudy (anonymous):

put \[x=.9999...\]multiply by 10 \[10x=9.9999...\] \[10x-x=9\] subract \(x\) from both sides \[9x=9\] divide both sides by 9\[x=1\]

OpenStudy (anonymous):

Wow, thank you~

OpenStudy (agent0smith):

You can use the same method to re-write repeating decimals as fractions.

OpenStudy (anonymous):

do you know 7x-1<20

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