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OpenStudy (anonymous):
Solve for x on [0,2pi] Sin2x-cosx=o
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OpenStudy (anonymous):
Use your trig identies: sin2x = 2sinxcosx Then you can solve easily for x: 2sinxcosx-cosx=0 [add cosx to each side] 2sinxcosx=cosx [divide each side by cosx] 2sinx=1 [divide by 2] sinx=1/2 [take arcsin of both sides] x=____ [use the unit circle to find the arsin(1/2)]
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