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solve for y. \[y=a(x-h)^2 + k\] wil have it's vertex at \[(h,k)\] and if a>0 will open up, if a<0 will open down. if|a|<1 then the parabola will be compressed and if |a|>1 then it will be stretched.
how do i plug in that equation? y=?
you have to solve for y in the given equation.
i get that, im confused as to how to rearragne the terms
any help?
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start by dividing both sides by 8
(x+3)^2/8+6= y is what i have?
or (to write it another way) \[y=\frac{1}{8}(x+3)^2-6\]
then what?
what is h? what is k?
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perhaps @Psymon can help you from here,,, i need to leave now.
so (3, -6)?
help please :/
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