Question

someone plz explain this to me!
find the exact value of this expression.
cot^-1(-sqrt(3)). i know the answer is 5pi/6 but i don't understand how that came to be.

Answer 1

cot = cos/sin so you need to find the angle that gives -sqrt(3) for cos/sin

cos(5pi/6) = -sqrt(3)/2 and sin(5pi/6) = 1/2

=>cos(5pi/6)/sin(5pi/6)= (-sqrt(3)/2)/(1/2)=(-sqrt(3)/2)*(2/1) = -sqrt(3)

11pi/6 also works

cos(11pi/6) = sqrt(3)/2m and sin(11pi/6) = -1/2

Answer 2

thanks bro! :) really clear explanation. :)

Answer 3

you're welcome1 glad you like it!