Question

2(2k-1)=4(k-2)

Answer 1

When you distribute, you find that both sides are equal. When this happens, the solution is all real numbers

Answer 2

2(2k - 1) = 4(k - 2)
4k - 2 = 4k - 8
4k - 4k = -8 + 2
0 = -6

are you sure....wouldn't it be no solutions ???