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3x + 5 < 6x - 1
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You can solve this like a normal equation. Only minor things change. 3x + 5 < 6x - 1 3x + 6 < 6x (Upon adding 1) x + 6 < 2x (Upon dividing by 3) 6 < x (Upon subtracting x)
subtract 3x on both sides, then add one , lastly divide by three on both sides to get 2<x 3x+5<6X-1 5<3x-1 6<3x 2<x
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