An acute angle θ is in a right triangle with sin θ = five sixths. What is the value of cot θ?

I need help, I don't understand the steps

Question

An acute angle θ is in a right triangle with sin θ = five sixths. What is the value of cot θ?

I need help, I don't understand the steps

anonymous · Answer

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anonymous · Answer

there is a picture of an angle whose sine is $\frac{5}{6}$
all that is missing is the third side, which you find via pythagoras
once you have all three sides, you can find any ratio that you like

anonymous · Answer

cotangent will be "adjacent over opposite"

anonymous · Answer

so i just  times the 5 again and o the same to the 6 to get what it equals?

anonymous · Answer

?

anonymous · Answer

would it be 25 & 36?

anonymous · Answer

no

anonymous · Answer

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anonymous · Answer

$$a^2+5^2=6^2$$ by pythagoras so 
$$a^2=6^2-5^2=36-25=11$$ making $a=\sqrt{11}$

anonymous · Answer

I meant to say that but it came out wrong, so now would I have to do $$\sqrt{11}/5$$