Question

An acute angle θ is in a right triangle with sin θ = five sixths. What is the value of cot θ?

I need help, I don't understand the steps

Answer 1

there is a picture of an angle whose sine is \(\frac{5}{6}\)
all that is missing is the third side, which you find via pythagoras
once you have all three sides, you can find any ratio that you like

Answer 2

cotangent will be "adjacent over opposite"

Answer 3

so i just times the 5 again and o the same to the 6 to get what it equals?

Answer 4

?

Answer 5

would it be 25 & 36?

Answer 6

no

Answer 7

\[a^2+5^2=6^2\] by pythagoras so
\[a^2=6^2-5^2=36-25=11\] making \(a=\sqrt{11}\)

Answer 8

I meant to say that but it came out wrong, so now would I have to do \[\sqrt{11}/5\]