Question

cos[inverse tangent 5/12-inverse sin (-3/5)]

Answer 1

Hey Chels!
\(\Large \color{royalblue}{\text{Welcome to OpenStudy! :)}}\)

Answer 2

Hmmm let's see what we've got here...

Answer 3

\[\Large \cos\left[\arctan\left(\frac{5}{12}\right)-\arcsin\left(-\frac{3}{5}\right)\right]\]

\[\Large \arctan\left(\frac{5}{12}\right)=\phi\qquad\qquad \arcsin\left(-\frac{3}{5}\right)=\theta\]
Hmm this one is a bit tricky, we'll have to draw 2 separate reference triangles.

Answer 4

\[\Large \arcsin\left(-\frac{3}{5}\right)=\theta \qquad\to\qquad \sin \theta=-\frac{3}{5}\]

Answer 5

Understand how to label the triangle? :o