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The region in the first octant bounded by the coordinate planes, the plane y = 1-x, and the surface z=cos([pi]x/2), 0
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Did you try arccos(z)?
you mean |dw:1380179041507:dw|
since sec^-1x is what i just drew and the cos^-1x version is negative.
how can arccos(x) fit the picture.... I mean you have this integral...|dw:1380179256255:dw|
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