Question

PLEASE HELP!!!!!! identify the vertex and the axis of symmetry for graph of the function
y=3(x+2)^2-3

A. Vertex (2,-3) <---------- my answer not sure if its right
axis of symmetry x=2
B vertex (-2,-3)
axis of symmetry x=-2
C vertex (2,3)
axis of symmetry x=2
D vertex (-2,3)
axis of symmetry x=-2

Answer 1

@ganeshie8 do you know this ?

Answer 2

vertec form :-

\(\large y = a(x-h)^2 + k \)

vertex = \( (h, k) \)
axis of symmetry : \(x=h\)

Answer 3

\(\large y=3(x+2)^2-3 \)

\(\large y=3(x- (-2))^2+ (-3) \)

Answer 4

compare it wid above,

\(h = -2\)
\(k = -3\)

so... ?

Answer 5

so it would end up being b and the axis of symmetry is -2?

Answer 6

Yes !

Answer 7

thank you! :)

Answer 8

np :)