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OpenStudy (anonymous):
PLEASE HELP!!!!!! identify the vertex and the axis of symmetry for graph of the function y=3(x+2)^2-3 A. Vertex (2,-3) <---------- my answer not sure if its right axis of symmetry x=2 B vertex (-2,-3) axis of symmetry x=-2 C vertex (2,3) axis of symmetry x=2 D vertex (-2,3) axis of symmetry x=-2
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OpenStudy (anonymous):
@ganeshie8 do you know this ?
ganeshie8 (ganeshie8):
vertec form :- \(\large y = a(x-h)^2 + k \) vertex = \( (h, k) \) axis of symmetry : \(x=h\)
ganeshie8 (ganeshie8):
\(\large y=3(x+2)^2-3 \) \(\large y=3(x- (-2))^2+ (-3) \)
ganeshie8 (ganeshie8):
compare it wid above, \(h = -2\) \(k = -3\) so... ?
OpenStudy (anonymous):
so it would end up being b and the axis of symmetry is -2?
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ganeshie8 (ganeshie8):
Yes !
OpenStudy (anonymous):
thank you! :)
ganeshie8 (ganeshie8):
np :)
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