Question

Write the equation of the line that is perpendicular to the line 3x + y = 7 and passes through the point (6, −1).

y = one thirdx − 3

y = one thirdx + 17

y = −3x − 3

y = −3x + 17

Answer 1

(y-y1)=m(x-x1)
m=slope
(x1,y1) is the point simplify to get answer

Answer 2

here slope is 3
since product of perpendicular slopes is -1

Answer 3

the slope of perpendicular line is the negative reciprocal?

+1/3 m
(y+1)=1/3(x-6)

y + 1 = 1/3 x -2
y= 1/3 -3