Question

write the value of (8 / 27) to the negative power of a third

Answer 1

So, what you really want is to find an x such that:

\[\Large x^{-3}=\dfrac{8}{27}\]

So one approach is to take each side of that equation to the reciprocal power... eg:

\(\Large (x^{-3})^{-1/3}=\left(\dfrac{8}{27}\right)^{-1/3}\)

Which gives you \(\Large (x^{-3})^{-1/3}=x\) on the left hand side, so evaluate the right hand side and that it what you need to take to the power -3 to get \(\Large \dfrac{8}{27}\)