Question

Geometry help please

Answer 1

apply pythagorus theorem two times

Answer 2

How?

Answer 3

apply pythagorus in bdc
and then in adb

Answer 4

Ohh ok. Thank you

Answer 5

(bc)^2=(bd)^2+(dc)^2

& (ab)^2=(ad)^2+(bd)^2

so ac=ad+dc

Answer 6

\(\bf BC^2 = DC^2+BD^2 \implies \sqrt{BC^2-BD^2} = DC\\ \quad \\
BA^2 = AD^2 + BD^2\implies \sqrt{BA^2-BD^2} = AD\)