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f(x)=2x+4; find f(3x)-3f(x)
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\(\bf f(x)=2x+4\\\\ \quad \\ f(3x) = \color{red}{2(3x)+4}\\ 3f(x) = \color{blue}{3 \times (2x+4)}\\ \quad \\ \quad \\ f(3x)-3f(x) = [\color{red}{2(3x)+4}] \quad - \quad [\color{blue}{3 \times (2x+4)}]\)
i tried pluging them in but i'm gettting confused
\(\bf f(x)=2x+4\\\\ \quad \\ f(3x) = 2(3x)+4\implies 6x+4\\ 3f(x) = 3 \times (2x+4)\implies 6x+12\\ \quad \\ \quad \\ f(3x)-3f(x) = [6x+4] \quad - \quad [6x+12]\)
-[ 6x + 12] = -6x - 12x
what would that give you?
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-6x-12
\(\bf f(3x)-3f(x) = [6x+4] \quad - \quad [6x+12]\implies \cancel{6x}+4\cancel{-6x}-12\)
-8
see where i messed up was i got 6x-fx+4 don't know how i did that
it happens, tis ok :)
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