At what point on the graph of y=2x^3/2 is the tangent line perpendicular to the line 2x+3y=6?
A) (0,0)
B) (1/16 , 1/32)
C) (3/2, 3(sqroot6)/2)
D) (1/4, 1/4)
E) ( 3/16, 3(sqroot3)/ 32)
Right now i have y=-2/3x+2
Perpendicular slope= 3/2

Question

anonymous · Answer

Fitst find the slope of the second equation. Then change flip and change sign. Then find the derivative of first function and set them equal.

anonymous · Answer

i find the derivative of y=2x^3/2?

anonymous · Answer

and set it equal to what?