Question

I need help with 3 Algebra 1 problems .
Medal & Fan !

Answer 1

What problems do you need help with?

Answer 2

The perimeter of a rectangle is 64 units. Can the length x of the rectangle can be 20 units when its width y is 11 units?

No, the rectangle cannot have x = 20 and y = 11 because x + y ≠ 64.

No, the rectangle cannot have x = 20 and y = 11 because x + y ≠ 32.

Yes, the rectangle can have x = 20 and y = 11 because x + y is less than 64.

Yes, the rectangle can have x = 20 and y = 11 because x + y is less than 32.

Answer 3

The table shows the solution to the equation |2x – 3| - 1 = 2:


Step 1 |2x – 3| = 2 + 1
Step 2 |2x – 3| = 3
Step 3 2x – 3 = 3 or 2x + 3 = 3
Step 4 2x = 6 or 2x = 0
Step 5 x = 3 or x = 0


Which is the first incorrect step?
Step 1

Step 3

Step 5

Solution is correct

Answer 4

Choose the missing step in the given solution to the inequality -x - 10 > 14 + 2x.


-x - 10 > 14 + 2x

-3x -10 > 14

x < -8


-3x > 24

-3x < 4

-3x > -4

8 < x

Answer 5

ok so on the -x-10 > 14+2x
whats missing is the 3rd step
before you divide by the -3 you need to add youy 10 to the other side so that your variable is isolated. The missing step is -3x > 24 Does that make sense?

Answer 6

Yea ! omg thank you . Can I ask you one more ?

Answer 7

lol yea and ill answer the other 2 also

Answer 8

On the
\[\left| 2x-3 \right|=2+1\]
Both answers are correct plug in both equations plugging in 3 gives
l2*3-3l=3 l6-3l=3 3=3
on the x=0
l2*0-3l=3 l-3l=3 (because of the absolute values our - becomes + so 3=3

In conclusion none of the steps are wrong.

Answer 9

If anything does not make sense just speak up

Answer 10

On your first one about the perimeter of a rectangle. P=2l+2w basically adding up all the sides. If the perimeter did = 64 then 20+20+11+11would equal 64 and does it?

Answer 11

looking at the answers they are asking just about x+y so only half the perimeter which would be half of 64.

So does 20+11=32?

Answer 12

Answer:

No, the rectangle cannot have x=20 and y=11 because x+y does not equal 32

Answer 13

Sorry i didnt see you replied !
other question was ;

The sum of two consecutive odd integers is 244. What is the smaller integer?

119

125

123

121

Answer 14

x+(x+2)=244
subtract the 2 from both sides
2x=242
divide by 2 to both sides
x=121

Answer 15

Thank you SO much !

Answer 16

it was no problem :) is there any more I can help you with?

Answer 17

Which of the following is not a way to represent the solution of the inequality 2(x - 1) -12?

x -5

x -5

-5 x

A number line with a closed circle on negative 5 and shading to the right

Answer 18

ok im not sure what you are looking at so let me get this right.
the equation is
\[2(x-1)-12\]

Answer 19

yes

Answer 20

well i get x=7 is that what the equation is asking for?

Answer 21

I think it's like the line with the closed or open circle . idk what it's called we can skip that question .

Answer 22

Jasmine wants to use her savings of $1128 to buy video games and music CDs. The total price of the music CDs she bought was $72. The video games cost $43 each. What is the maximum number of video games that Jasmine can buy with her savings?

24

25

26

27

Answer 23

oh maybe the equation is 2(x-1)>12??

Answer 24

2(x-1) > <- ( Line under that ) -12

Answer 25

\[2(x-1) \ge -12\]

Answer 26

yes (:

Answer 27

ok! now i got it lol

Answer 28

Haha sorry i didnt realize that it didnt show those

Answer 29

oh no its cool haha i see what they want now

Answer 30

so the answer would be \[x \ge -5 \] do you see how i get that?

Answer 31

yeah I got the same but i was unsure of it

Answer 32

Which of the following is not a way to represent the solution of the inequality 8x - (5x + 4) -31?

x -9

-9 x

A number line with a closed circle on -9 and shading to the left

A number line with a closed circle on -9 and shading to the right

Answer 33

ok bad drawing but thats what your graph will look like. make sense? your x needs to be greater than negative 5 so shade the bigger numbers. and its a closed circle because its greater then and equal to.