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Algebra
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6x^2/7x^4
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\[\frac{a^b}{a^c}=a^{b-c}\] so you have \[\frac{6x^2}{7x^4}=\frac{6}{7}\frac{x^2}{x^4}=\frac{6}{7}x^{2-4}=\frac{6}{7}x^{-2}=\frac{6}{7x^2}\]
i dont understand
which part?
do you understand that \[\frac{6x^2}{7x^4}=\frac{6}{7}*\frac{x^2}{x^4}\]?
yeah
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ok well now we just use the property i showed when we \[\frac{x^a}{x^b}=x^{a-b}\]so \[\frac{x^2}{x^4}\space becomes\space x^{2-4}=x^{-2}=\frac{1}{x^2}\]
ok
example: \[\frac{2^3}{2^2}=2^{3-2}=2\]
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