what would the resulting polypeptide look like if the sequence is (AUG/CGU/CCC/AAC/CGC/AGC/AAU/UUU/UGG/GGC/UAA/UGU/AG
TUC/GCU/GGG/TTG/GCG/TCG/TTU/UUU/UCC/CCG/UTT/UCU/TC ?
if u want a polypeptide then each codon codes for 1 amino acid...starting from AUG ehich codes for methionine and so on,...
do u want me 2 explain in detail?
Yes please
u know that there are 4 bases A C G T in the DNA rite? and in RNA T is replaced by U
u der?
yes
u wid me so far?
yes
i have the trna as AUG/CGU/CCC/ACC/GCA/GCA/AUU/UUU/GGG/GCU/AAU/GUU/C
are u sure dis is ur tRNA?
See every rRNA has a start codon...which is AUG and tRNA has its complementary...so it wud be UAC
this was the very first strand Dna original -ATGCGACCCAAACCGCAGCAATTTTTGGGGCTAATGTAG WHICH I TRANSLATED TO TACGCTGGGTTTGGCGTCGTTAAAAACCCCGATTACATC
THE RNA -AUGCGACCCAAACCGCAGCAAUUUUGGGGCUAAUGUAG
THAN TRNA AUGCGUCCCAAACCGCAGCAAUUUUUGGGGCUAAUGUAG WHICH I THAN TRANLATED TO METARGPROLYSPROGINGINPHELEUGLYLEUMETUAG
AND THE LAST QUESTION IS SUPPOSE THERE WAS A DELETION OF THE SECOND A IN THE MRNA- WHAT WOULD THE RESULTING POLYPEPTIDE LOOK LIKE AND THE STAND AUG/CGU/CCC/AAC/CGC/AGC/AAU/UUU/UGG/GGC/UAA/UGU/AG
ATGCGACCCAAACCGCAGCAATTTTTGGGGCTAATGTAG this is "TRANSCRIBED" into mRNA UACGCUGGGUUUGGCGUCGUUAAAAACCCCGAUUACAUC this is ur mRNA.
ur sequence is right...but all the T's should be replaced by U because u r writing a RNA...
UACGCUGGGUUUGGCGUCGUUAAAAACCCCGAUUACAUC
with me so far?
YES
yes...now u r correct....
GREAT
now check which codon codes for wat....codon is on mRNA and anticodon on tRNA
So AUG on mRNA codes for methionine. and d anticodon UAC on tRNA codes for methionine.
SO IT WOULD BE METARGPROLYSPROGINGINPHELEUGLYLEUMETUAG
RIGHT
no it wud not...
now in ur mRNA u hv d first codon as UAC which codes for tyrosine
UAU OR UAC
correct
so u hv d table which shows which codon codes for wat rite? starting from uac-tyrosine...go ahead in this manner.
UAC/GCU/GGG/UUU/GGC/GUC/GUU/AAA/AAC/CCC/GAU/UAC/AUC TYR/ALA/GLY/PHE/GLY/GLY,VAL/LYS/ASN/PRO/ASP/TYR/LLE
IS THAT RIGHT
i want to ask u d seq that u have given is part of a gene? bcuz every mRNA sequence starts with a start codon AUG which in this case is not....while translating if the ribosomes do not find the start codon the mRNA chain is not translated.
SHOULD BE THE AUGCGUCCCACCGCAGCAAUUUUUGGGGCUAAUGUUC
THAT IS WHAT I HAVE
no....see the sequence that u gave me is the DNA seq rite? so to make it into an rna u write the complementary base and instead of T u write U correct?
the original strand that u gave me is dis? u gave me a double strand seq? ATGCGACCCAAACCGCAGCAATTTTTGGGGCTAATGTAG TACGCTGGGTTTGGCGTCGTTAAAAACCCCGATTACATC
u der? i thot u gave me just 1 strand of dna and d oder strand was the transcribed mRNA.
then u r right...u take the strand which moves from 5' to 3' direction and transcribe into mRNA and then check which codon codes for wat....u are right
sorry for the confusion...the way u wrote it confused me...my bad
u r absolutely right.
so than what would be considered the 5'3?
what would it be called?
ummm.....consider the strand whose first 3 nucleotides complementary are AUG. it is just a strand of DNA. but during transcribing that strand is called the template strand and the other strand is called the coding strand.
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