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Solve x^2 - 121 = 0
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11 ?
Hi, do u know how to write 121 as a square of another number ... i.e 121 = x^2 wht will be "x"?
11
a^2 - b^2 = (a+b)*(a-b) So, x^2 - 121 can be written as (x)^2 - (11)^2 So, it is (x+11)*(x-11) = 0 Therefore, (x+11)=0 x = -11 and (x-11)=0 x = 11
Thanks Guyss ! @Dharmaputra_993 & @***[ISURU]***
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