Question

can you guys help me with one more its

Evaluate f(x) = x^ 2 + 1 for f(10).

a.2√2
b.101
c.21

Answer 1

Hi,
substitute 10 instead of "x" in f(x)
f(x) = x^2 +1
= 10^2 + 1
= 101

hope this will help ya!!

Answer 2

These are harder can you help with this one too?

If f(x) = x^ 2 + 1, find f(a + 1).


a.a^2 + 2
b.a ^2+ a + 1
c.a ^2+ 2a + 2

Answer 3

hi,
use the same method
substitute (a + 1) instead of "x"
f(x) = x^2 + 1
= (a + 1)^2 + 1
= a^2 +2a +1 +1
= a^2 + 2a +2

Answer 4

thanks how about

Given the function f(x) = 3x + 1, evaluate f(a + 1).

a.3a + 1
b.3a + 2
c.3a + 4

Answer 5

use the same old method here lol
f(a+1) = 3(a + 1) +1
now simplify it
3a +1 +1
3a +2

Answer 6

ok last one

If f(x) = 3x + 1, then f(a + h) - f(a) =


a.h
b.3h
c.3h + 2

Answer 7

At least try it yourself first, magan... follow the examples @***[ISURU]*** showed.