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Mathematics 18 Online
OpenStudy (anonymous):

What is the simplified form of

OpenStudy (anonymous):

OpenStudy (anonymous):

x to the one half power x x2 square root of x

OpenStudy (zzr0ck3r):

\[\sqrt[4]{x^2}*\sqrt[4]{x^2}=x^{\frac{1}{2}}*x^{\frac{1}{2}}=x^{\frac{1}{2}+\frac{1}{2}}=x^1=x\]

OpenStudy (zzr0ck3r):

\[\sqrt[4]{x^2}*\sqrt[4]{x^2}=x^{\frac{2}{4}}*x^{\frac{2}{4}}=x^{\frac{2}{4}+\frac{2}{4}}=|x| \]

OpenStudy (anonymous):

okay! so simplify it then add the fractions. okay! got it! thanks

OpenStudy (zzr0ck3r):

note that I kept the fractions in unreduced form because we didnt want to loose the information that this is always positive.

OpenStudy (zzr0ck3r):

its very important to understand why I said =|x| and not =x do you?

OpenStudy (zzr0ck3r):

\[x^2\ge 0\] so \[\sqrt[4]{x^2}\ge0\] so \[\sqrt[4]{x^2}*\sqrt[4]{x^2}\ge0\]

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