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Find the zeros of the polynomial function and state the multiplicity of each. f(x) = 3(x + 8)^2(x - 8)^3
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set y = 0 that's why is called the "zeros of the polynomial" which is really just where the x-axis is touched by the graph, or the x-intercepts
\(\bf y = 3(x + 8)^2(x - 8)^3\implies 0= 3(x + 8)^2(x - 8)^3\\ \quad \\ 0 = (x + 8)^2(x - 8)^3\\ \quad \\ 0 = (x + 8)(x + 8)(x - 8)(x - 8)(x - 8)\)
-8, multiplicity 3; 8, multiplicity 2 ? @jdoe0001
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