Question

sghf

Answer 1

I'll do the first one to get you started

f(x) = 9x - 2

f(g(x)) = 9( g(x) ) - 2

f(g(x)) = 9( -x + 3 ) - 2

f(g(x)) = -9x + 27 - 2

f(g(x)) = -9x + 25

Answer 2

that is correct

Answer 3

that's great it's making sense now

Answer 4

is the second problem

\[\large f(x) = \frac{24}{3x-2}\]

??

Answer 5

ok then yes, you replace x with -2 and evaluate


\[\large f(x) = \frac{24}{3x-2}\]


\[\large f(-2) = \frac{24}{3(-2)-2}\]


\[\large f(-2) = \frac{24}{-6-2}\]


\[\large f(-2) = \frac{24}{-8}\]


\[\large f(-2) = -3\]

Answer 6

you're welcome