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A line has a slope of −23 and goes through the point (−5,2). If the point (37,b) lies on the line, what is the value of b?
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Remember the equation for the slope \(m\) given two points \((x_1,y_1),(x_2,y_2)\)\[ m=\frac{y_2-y_1}{x_2-x_1} \]
In this case\[ -23 = \frac{b-2}{37-(-5)} \]
You need to solve for \(b\)
so the bootom equals 42?
Yes.
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so whats the answer buddy (:
You need to solve for \(b\).
\[ -23=\frac{b-2}{42} \]
What do you do next to isolate the variable?
so its -966?
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-968
i got -966
we had to do cross multiply
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