Question

A rectangle has an unknown width and length. The length is 4 less than twice the width. The area of the rectangle is 16. What is the width and length of the rectangle?

Answer 1

Need help!!

Answer 2

w = width
l = length

"length is 4 less than twice the width"

"twice the width" => 2w

"4 less than twice the width" => 4- 2w


\(\bf w = width\qquad \qquad l = length=4-2w\\ \quad \\
Area = 16 = l\times w\implies (4-2w)\times w\\ \quad \\ \quad \\

16 = (4-2w)\times w\)

solve for "w" to know what the width :)
whatever the width will be, the length will be, 4 -2w

Answer 3

hmmm.... actually hold on, 4 less than twice will be 2w-4

so lemme rewrite that quick :)

Answer 4

\(\bf w = width\qquad \qquad l = length=2w-4\\ \quad \\
Area = 16 = l\times w\implies (2w-4)\times w\\ \quad \\ \quad \\

16 = (2w-4)\times w\)

solve for "w" to know what the width :)
whatever the width will be, the length will be, 2w-4