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x2−6x−16=0
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\[x^2-6x-16=0\]we want 2 numbers that multiply to -16 and add to -6 what are these two numbers?
-2,8
so since we dont have a coefficient on the first term we know the answer is (x+2)(x-8)
note that if we plug in -2 or 8 we get 0
yeah
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