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write the expression in comlete factored form. 2c(u-6)+(u-6)
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you have two terms
in each term there is a common thing, pull that out
2c(u-6)+(u-6) ^^^ ^^^^
(u-6)( ? + ? )
i thoug6 was in the second set of parentheses
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entire (u-6) we took as common factor
2c(u-6)+(u-6) ^^^ ^^^^
oh okay
when u take away (u-6) from first term, wat stays back ?
2c stays back right ?
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2c(u-6)+(u-6) ^^^ ^^^^ (u-6)(2c + 1)
we're done ! in the 2nd term 1 stays back
see if thats more/less makes sense
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