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How do I solve for a? 3x-5a/a=y
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\[\frac{5x-a}{a}=y\] like that?
3x-5a over a
\[\frac{3x-5a}{a}=y\]
that one?
\[\frac{ 3x - 5a }{ a }=y\] \[\frac{ 3x }{ a } - \frac{5a}{a} = y\] The 5a/a becomes 5 because a/a is cancelled out. \[\frac{ 3x-5 }{ a }=y\] \[3x-5=ya\] \[\frac{ 3x-5 }{ y }=a\]
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Sorry, I made a mistake in the equation. The correct solution after a/a is cancelled out from 5a/a is: \[\frac{ 3x }{a}-5=y\] \[\frac{ 3x }{ a }=y+5\] which is the same as \[\frac{ 3x }{ y+5 } = a\]
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