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A rock is thrown downward from an unknown height above the ground with an initial speed of 26 m/s. It strikes the ground 4.1 s later. Determine the initial height of the rock above the ground. Theacceleration of gravity is 9.8 m/s 2 .
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\[h_0+26t-19.6t^2=0\] put \(t=4.1\) and solve for \(h_0\)
okay, thats what i thought. thank you.
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