Question

find f^-1(x)
f(x)=x^2-4, x>_0

Answer 1

f^-1(x) is the inverse
change around the y with x
so x=y^2-3
x-2=y^2
y=(x-2)^1/2

Answer 2

lol i like how the 4 changed to a 3 and then to a -2 :P

Answer 3

oh lol brain fart... :p
x=y^2-4
x-4=y^2
y=(x-4)^1/2

Answer 4

hehe it's cool. but (x+4)^(1/2) btw

Answer 5

lol :D
i can't maf

Answer 6

lol