Ask your own question, for FREE!
Mathematics 6 Online
OpenStudy (anonymous):

for every real number x, if x²>1, then x>1. true or false?

OpenStudy (anonymous):

just kidding false i wasnt paying attention to the second part. the first one is true because even if its negative whn multiplied by its self its going to give you a positive but if its negative then false for the second one

OpenStudy (anonymous):

\[x²>1 \rightarrow x> \pm1\] Therefore Either \[\ x> 1 \] or x> -1 Thus x>1 is one of the solutions, which should be considered as TRUE. @myonlystory

OpenStudy (dls):

@dpasingh You're ABSOLUTELY wrong. Its false.

OpenStudy (dls):

What if x=-2? x^2>1 x<1

OpenStudy (anonymous):

exactly ^

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!