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for every real number x, if x²>1, then x>1. true or false?
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just kidding false i wasnt paying attention to the second part. the first one is true because even if its negative whn multiplied by its self its going to give you a positive but if its negative then false for the second one
\[x²>1 \rightarrow x> \pm1\] Therefore Either \[\ x> 1 \] or x> -1 Thus x>1 is one of the solutions, which should be considered as TRUE. @myonlystory
@dpasingh You're ABSOLUTELY wrong. Its false.
What if x=-2? x^2>1 x<1
exactly ^
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