Question

f(x)=3x^2+1 find f(x+3)-[f(x)+3]
help me solve this please.

Answer 1

@Hero

Answer 2

i know that we start of with f(x+3)=3(x+3)^2+1

Answer 3

but everytime i expand its not right

Answer 4

f(x+3)=3(x+3)^2
now put the value of f(x) and f(x+3) as asked in ques u will get the ans

Answer 5

yes the last one i have the correct answer to

Answer 6

and the first one it's like i can only write it out but when i expand i mess it up

Answer 7

i should get 18x +24 for final answer

Answer 8

Find f(x + 3):
f(x+3) = 3(x+3)^2 + 1
= 3(x^2 + 6x + 9) + 1
= 3x^2 + 18x + 27 + 1
= 3x^2 + 18x + 28

Then find f(x) + 3:
f(x) + 3 = 3x^2 + 1 + 3
= 3x^2 + 4

so

f(x + 3) - (f(x) + 3) = (3x^2 + 18x + 28) - (3x^2 + 4)

Finish it..

Answer 9

(3x^2-3x^2) +12x(28-4)
18x+24

Answer 10

f(x+ 3) - (f(x) + 3) = (3x^2 - 3x^2) + 18x + (28 - 4)
= 18x - 24

Answer 11

12x(28 - 4) is not a correct expression.

Answer 12

(3x^2-3x^2) +18x+(28-4)

Answer 13

Yes, that is correct

Answer 14

okay

Answer 15

final will be 18x-24

Answer 16

thanks for helping me @hero