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A particle is accelerated uniformly from rest to a speed of 50m/s in 5 seconds. The average speed of the particle during this 5sec time interval is....
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\[avg speed =\Delta d \div t\]
Is delta(d) displacement or distance?
is average displacement is with delta displacement average speed is with delta distance, meaning you add the distance to get a total
so it would be 50 + 0
Sorry, I don't quite understand, but the logical answer seems to be 10m/s.
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