Find the 6th term of the sequence
an=an-1 +8 where a1=10

please show work

Question

Find the 6th term of the sequence               
an=an-1 +8     where a1=10

please show work

tkhunny · Answer

Well, you had better start showing your work!

a2 = a1 + 8

a1 = 10

a2 = 10 + 8 = 18

Okay, you do the next 4 and you'll be done.

anonymous · Answer

why did you put a2

anonymous · Answer

see n in this case denotes the number of terms....

anonymous · Answer

so for finding 6th term ....put n=6
a6=a5+8

anonymous · Answer

oh okay so now what

tkhunny · Answer

It's a sequence.  That's what the notation means.  It should be a subscript.

$a_{2} = f(a_{1}) = a_{1} + 8$

The formula is this:  $a_{n} = f(a_{n-1}) = a_{n-1} + 8$

This says only that the value of each member of the sequence is eight (8) greater than the previous member.

anonymous · Answer

what now

tkhunny · Answer

Whaat now, what?  Do you have $a_{2}$?  If so, calculate $a_{3}$.  Do you have $a_{3}$?  If so, calculate $a_{4}$ and so on...