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Mathematics 17 Online
OpenStudy (anonymous):

So lost: For what value of the constant c is the function f continuous on (-inf, +inf) where *comments*

OpenStudy (anonymous):

hero (hero):

try setting \[t^2 - c = ct + 2\] then let t = 4. Afterwards solve for c.

hero (hero):

lolling at the file name

OpenStudy (anonymous):

Just evaluate both versions of the formula at s = 9. cs + 6 = 9c + 6 cs^2 - 6 = 81c - 6 Function will be continuous if these are the same. Solve 81c - 6 = 9c + 6

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