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Physics 39 Online
OpenStudy (anonymous):

The period of the earth around the sun is 1 year and its distance is 150 million km from the sun. An asteroid in a circular orbit around the sun is at a distance 185 million km from the sun. Period of the asteroid is 1.369 years. What is the orbital velocity of the asteroid? Assume there are 365 days in one year. Answer in units of m/s

OpenStudy (theeric):

Here are a couple hints! If you still need help, I'm sure someone else on here would be glad to! 1. You can find the distance of the path around the Sun. It is the circumference when the radius is 184 million km. 2. You can find the velocity by dividing the distance by the time it takes. The time it takes, per round trip, is the "period," 1.369 years. |dw:1380580931104:dw| Then you'll need to do some conversions! The 365 days per year will help you with that. There are 24 hours per day, 60 minutes per hour, and 60 seconds per minute. There are 1000 meters per kilometer.

OpenStudy (anonymous):

Thanks :)

OpenStudy (theeric):

You're welcome! Any questions? I didn't know you were on!

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