Question

(3a4)3
(-2x3y)4
(-mn8)2
(3x3y)2(-4x2y4)3

Answer 1

solve

Answer 2

each one is a new equation

Answer 3

1. take 3 and multiply it by 3a and then by 4
2.take 4 and multiply it by 2x and then by 3y
3.take 2 and multiply it by -mn8
4.take 2 and multiply it by 3x then 3y then take 3 and multiply it by -4x then by 2y then by 4 4

Answer 4

1=9a12
2=-8x12y
3=-2mn16
4=-6x

Answer 5

\( (a^m)^n = a^{mn}\)

1. \( (3a^4)^3 = (3^1a^4)^3 = 3^{3 \times 1}a^{4 \times 3} = 3^3a^{12} = 27a^{12}\)

Answer 6

2. \((-2x^3y)^4 = (-2)^4(x^3)^4 y^4 = 16x^{12}y^4\)

Answer 7

so is that the final answer

Answer 8

Those are the final answers for 1 and 2.