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Pre-Algebra
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3(q+4)+4q+1
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can you please help me
is it suppose to be 3(q+4)=4q+1
no its not
Simplifying 3(q + 4) + 4q + 1 = 0 Reorder the terms: 3(4 + q) + 4q + 1 = 0 (4 * 3 + q * 3) + 4q + 1 = 0 (12 + 3q) + 4q + 1 = 0 Reorder the terms: 12 + 1 + 3q + 4q = 0 Combine like terms: 12 + 1 = 13 13 + 3q + 4q = 0 Combine like terms: 3q + 4q = 7q 13 + 7q = 0 Solving 13 + 7q = 0 Solving for variable 'q'. Move all terms containing q to the left, all other terms to the right. Add '-13' to each side of the equation. 13 + -13 + 7q = 0 + -13 Combine like terms: 13 + -13 = 0 0 + 7q = 0 + -13 7q = 0 + -13 Combine like terms: 0 + -13 = -13 7q = -13 Divide each side by '7'. q = -1.857142857 Simplifying q = -1.857142857
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