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Mathematics 13 Online
OpenStudy (anonymous):

how do i find the horizontal asymptote of the equation y=(2x+1)/(x^2-x) ?

OpenStudy (jmark):

Given equation y=(2x+1)/(x^2-x) find horizontal asymptote hence (2x+1)/(x^2-x)->0 as x->± ∞ Learn more about Horizontal Asymptote Calculator http://goo.gl/W3Qs4C

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