Question

solve the system by elimination

Answer 1

Do you know where to start?

Answer 2

I honestly suck at this so no

Answer 3

Mkay, no worries:) I'll do this one step by step, so you can see how it's done

Answer 4

thank you so much

Answer 5

5(x+5y-4z=-10 ) ( get two equations and find a variable that can be eliminated)
4 ( 2x-y+5z=-9) (by multiplying a number by the whole equation, like 5 & 4)
5x+25y-20z=50 ( as you can see -20+20=0 see eliminate z and add/subtract the rest)
8x-4y+20z=-36
3x-29y=14 <------- Keep this equation for later use

2x-y+5z=-9 (get two equations and do the same thing)
2x-10y-5z=0 (I used the second equation and the last one) (z gets eliminated )
4x-11y=-9 <----------- use this equation with the other one

-4( 3x-29y=14) (Do the same thing, multiply and eliminate)
3(4x-11y=-9)
-12x+116y=-56 (x is eliminated)
12x-33y-27

83y=-83 (y=-1 , so now we plug it in into an equation and from there we will get
y=-1 the rest of the solutions)

x+5(-1)-4z=-10
x-1-4z=-10
+1 +1
x-4(0)=-9
+4 +4
x=-5

x=-5 ,y=-1,z=0

Answer 6

Sorry,if It's not so well explained.

Answer 7

Also to check if your solutions are correct just plug them into an equation
(-5)+5(-1)-4(0)=-10
-5-5+0=-10

Answer 8

thank you so much!!!! that actually helped a lot :)