Question

anyoneee????

Answer 1

\(\bf \textit{keep in mind that } \quad tan(\theta)= \cfrac{\textit{opposite side}}{\textit{adjacent side}}\\ \quad \\
tan^{-1}(tan(\theta))= tan^{-1}\left(\cfrac{\textit{opposite side}}{\textit{adjacent side}}\right)\\\implies \theta = tan^{-1}\left(\cfrac{\textit{opposite side}}{\textit{adjacent side}}\right)\)

Answer 2

i got 36.67

Answer 3

well, I got a little less, \(\bf 35.53^o\)